Now, let's consider the two cases for the limit as $x$ approaches $1$ and $-1$.
Case 1: $x \rightarrow 1$
We can rewrite the function as $f(x) = \frac{\cos 2 - \cos 2x}{(x - 1)(x + 1)}$. Now, we can apply L'Hopital's rule to find the limit as $x \rightarrow 1$.
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