00:01
In this question, we have the function of f, and it's a parvoise function.
00:05
So given that, we need to find the f prime function and determine if the function is differentiable at 1.
00:15
So first, let's take the derivatives.
00:18
F prime of x is going to be, what is the derivative of 2 minus x? well, it's going to be 0 minus 1 because the derivative of 2 is a 0, and derivative of negative x is negative 1.
00:34
And that is for x less than one, not less than or equal to, because you have a parovized function and you have a pairwise function and you have a break in between the two functions.
00:48
So it's not going to be a smooth transition.
00:50
That means there's not going to be any slope.
00:54
And what's the derivative of x squared minus 2x plus 2? so the derivative of x squared is going to be 2x, negative 2x is going to be negative 2.
01:04
And for 2, is going to be zero.
01:11
So, as you can see, f is not differential at x equals to 1.
01:26
And let's also graph it and see it and be sure of it.
01:30
So let's first graph f.
01:33
So f is 2 minus x for x less than or equal to 1.
01:39
So i'm going to mark it over here.
01:44
So at 1, right, our value is 1, and the function is 2 minus x.
01:52
It's going to look like this.
01:55
And the continuation is going to be x squared minus 2x plus 1 plus 2.
02:03
It's going to be a quadratic equation, and it's going to be of the following form...