00:01
Suppose f of x is equal to the absolute value of x raised to x for x not equal to zero.
00:07
Now for this problem, we want to show that our function has a removable discontinuity at x equals 0, and you want to redefine this function so that it is continuous.
00:19
Now let's start with the fact that the absolute value of x, this is equal to negative x, if our x value is less than zero and this is positive x if x is greater than zero.
00:36
Now to show that the function has a removable discontinuity at x equals zero, we want to show that the limit as x approaches zero of this function is not equal to the value of f at zero.
00:56
So we first want to find the limit of f of x as x approaches zero and to do this, we want to find the one -sided limits and they must be equal.
01:08
Now the limit as x approaches zero from the left of the absolute value of x raised to x, since our x value is from the left of zero, then it must be less than zero.
01:24
So we, we will replace absolute value of x by negative x and this is equal to the limit as x approaches 0 from the left of negative x raised to x...