Let $g(x)=-\frac{f(-1)}{2} x^{2}(x-1)-f(0)\left(x^{2}-1\right)$
$+\frac{f(1)}{2} x^{2}(x+1)-f^{\prime}(0) x(x-1)(x+1)$ where $f$ is a thrice
differentiable function. Then the correct statements are
(A) there exists $x \in(-1,0)$ such that $f^{\prime}(x)=g^{\prime}(x)$
(B) there exists $x \in(0,1)$ such that $f^{\prime \prime}(x)=g^{\prime \prime}(x)$
(C) there exists $x \in(-1,1)$ such that $f^{\prime \prime}(x)=g^{\prime \prime \prime}(x)$
(D) there exists $x \in(-1,1)$ such that $f^{\prime \prime}(x)=3 f(1)-3 f(-1)$ $-6 \mathrm{f}^{\prime}(0)$