Question
Let $H$ be a proper subgroup of a finite group $G$. Show that $G$ is not the union of all conjugates of $H$.
Step 1
Suppose for the sake of contradiction that $G$ is the union of all conjugates of $H$. That is, for every $g \in G$, there exists an element $x_g \in G$ such that $g \in x_g H x_g^{-1}$. Show more…
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Let $G$ be an abelian group. If $H=\left\{x \in G: x=x^{-1}\right\}$, that is, $H$ consists of all the elements of $G$ which are their own inverses, prove that $H$ is a subgroup of $G$.
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