00:01
In this situation, we have a rectangle, and you could maybe imagine that it's expanding outwards from every corner and inwards, depending on how x, y, and l are all interacting here.
00:16
And the way that we could find out dx, d, d, y, d, d, t, d, l, dt, is by setting out pythagorean theorem, x squared, plus y squared, equals z squared.
00:27
And then we're going to differentiate with respect to t.
00:34
And so using the power rule for each of these, we'll get 2x, dx, dx, d, d, y, d, d, t, plus 2y d t, plus, or sorry, is equal to 2ldt.
01:07
Now, if any of these was fixed, let's say, for instance, just supposing that, like, x was a fixed length, then that dxdt would end up being zero, for instance.
01:21
And then that's for part a, and then for part b, we want to know very specific situation here.
01:30
When x is 3, we'll go ahead and start substituting in.
01:35
So, well, we'll do that underneath.
01:37
So we've got 2 times x is 3.
01:42
Dxdt is increasing, and it is increasing.
01:46
At a rate of one half, half a foot each second, plus two times y in this situation is four.
02:00
And then that's multiplied by d, y, dt, which that y side is actually decreasing at a rate of one -fourth of a foot.
02:11
So actually, this will be negative, one -fourth...