Let $\lambda$ be a list of real numbers. Define
$$
\text { sumsqr }(\lambda)=[\text { if } \lambda=() \text { then } 0 \text { else head }(\lambda) \operatorname{head}(\lambda)+\operatorname{sumsqr}(\operatorname{tail}(\lambda))] \text {, }
$$
where head $(\lambda)$ head $(\lambda)$ is the numerical product of the head of $\lambda$ with itself. The sumsqr function returns the sum of the squares of all members of $\lambda$. Now let $\lambda=\left(x_1 \cdots x_k\right)$ be any nonempty list of real numbers. Prove that: if $\operatorname{sumsqr}(\lambda)=0$, then every member of $\lambda$ is 0 . In other words, for $i=1, \cdots, k, x_i=0$. Use induction on $k=\operatorname{length}(\lambda)$, and assume basic properties of the real numbers.