00:01
Okay, so here for part 8, we first want to show that g is closed under multiplication.
00:06
So if we let g be a group in x and y be elements in g, then there are going to exist n and m that are elements of the positive integers.
00:18
Therefore, we get x to the n, which is going to be equal to y to the m, which is going to be equal to 1.
00:25
So then we get that x, y, to the m, n is equal to x to the n to the m times y to the n to the m, which is just equal to 1 times 1, which is equal to 1.
00:40
So therefore, x times y is an element of g, and therefore that g is closed under multiplication.
00:47
And then multiplication on g is associative because multiplication on the complex numbers is associative.
00:54
So therefore we get that g is going to be associative under multiplication.
00:58
And we now want to show that g has a unique identity.
01:02
So we know that one to the one is equal to one.
01:05
So therefore we know that one is an element of the group g.
01:09
So then to show that for all x in g, we get that one times x is equal to x times one, which is equal to x.
01:16
Therefore, one is the identity in g under multiplication...