Question
Let $\mathbf{S}$ be the subspace of $\mathbf{R}^{4}$ containing all vectors with $x_{1}+x_{2}+x_{3}+x_{4}=0$. Find a basis for the space $S^{\perp}$, containing all vectors orthogonal to $S$.
Step 1
This means that any vector in $\mathbf{S}$ can be written as $(x_{1}, x_{2}, x_{3}, -x_{1}-x_{2}-x_{3})$. Show more…
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Key Concepts
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(a) Find a basis for the subspace $\mathbf{S}$ in $\mathbf{R}^{4}$ spanned by all solutions of $$ x_{1}+x_{2}+x_{3}-x_{4}=0 $$ (b) Find a basis for the orthogonal complement $\mathbf{S}^{\perp}$. (c) Find $b_{1}$ in $\mathbf{S}$ and $b_{2}$ in $\mathbf{S}^{\perp}$ so that $b_{1}+b_{2}=b=(1,1,1,1)$.
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