let-mathbfv_1leftbeginarrayr-1-3-4endarrayright-mathbfv_2leftbeginarrayr0-3-1endarrayright-mathbfv_3

Question

Let
$\mathbf{v}_{1}=\left[\begin{array}{r}{-1} \ {-3} \ {4}\end{array}ight], \mathbf{v}_{2}=\left[\begin{array}{r}{0} \ {-3} \ {1}\end{array}ight], \mathbf{v}_{3}=\left[\begin{array}{r}{1} \ {-1} \ {4}\end{array}ight], \mathbf{v}_{4}=\left[\begin{array}{r}{1} \ {1} \ {-2}\end{array}ight]$
$\mathbf{p}_{1}=\left[\begin{array}{r}{1} \ {-1} \ {2}\end{array}ight], \mathbf{p}_{2}=\left[\begin{array}{r}{0} \ {-2} \ {2}\end{array}ight]$
and $S=\left\{\mathbf{v}_{1}, \mathbf{v}_{2}, \mathbf{v}_{3}, \mathbf{v}_{4}ight\} .$ Determine whether $\mathbf{p}_{1}$ and $\mathbf{p}_{2}$ are inconv $S .$

Lucía Guerrero · Accepted Answer

again. One way we can use Thio. See if this points are in a complex. All of is by finding their very central coordinates and by checking that all of them are positive. One way to find their very centric coordinates is by writing H p I minus fee one as a linear combination. Off feed to my newsfeed. One 83 minus 31 Aunt B four minus 51. So we want to find cities three and four on. We can do that by reducing the following no rented matrix. So the first column is gonna be once you row ministry, which is V two minus 31 then 53. Ministry one on before Ministry one on. Then the next column is gonna be p one minus V one on finally p two minus V one. So we&#x27;re going to leave the first row as it iss on, then 1 to 2 to one on. Then we&#x27;re going to multiply the second Royal by one half onto the third road. We&#x27;re going to add three times the first row. Now we&#x27;re going to subtract one third of the third growth to the free throw. Andi, Also, we&#x27;re gonna subtract 1/6 off the third road to the second round and we&#x27;re going to divide the grove by six. Finally, we subtract a second road to the first row on we multiply the second role by one half. From here we can switch the 2nd and 3rd wrote on, We can create the values for C two, C three and C four. Um, we have one third of 50 minus 51 plus two Church fit three minus V one plus 1/6 of before minus 51 equals two p one minus +31 On. When we rewrite this expression, we obtain the following minus 16 to 51 plus 1 30 ft two plus the church of feet three, please. 1/6 off before equals to be one. Andi here since the first party century coordinate its negative. Then we conclude that P one is not in a complex whole. Off is on from the last calendar. For reduce matrix, we have that one third of feet to minus V one plus 1/6 off 53 minutes V one plus 16 before minus. V. One is the same as B two minus V. one on again. If we write this in the following way, one third of feet walk this one third feet too. Plus 1 63 3 plus 1/6 before equals to pick two. We can see that this linear combinations that this linear combination has all of its coefficients, which are positive numbers. Therefore, P two is in the comeback selloff s.

Gideon Idumah · Answer

for this question with a church if p is in the column off, eh? To do that, we must ensure that a X your calls a p most off his solution. So how do we do this with a check? If the augmented metrics or commended metrics A He&#x27;s consistent. So a P will be minus three 06 minus two. Sue three zero minus six, three one 14 minus nine cause this is speedy. No. What we do is we try to reduce these. We introduce your S O U C for all three equal to rule three. Lost to warn. This will put a zero on than its days. So why we do that? We&#x27;re gonna off minus three, Sue, so remind us too. 01 zero Sue minus 6 14 Then when you do this, you&#x27;re gonna off zero minus one three, minus seven. So next we try to introduce zero on the native. This true, that is, make these zero. And then to do dot She just 03 You called Zorro? Three plus off through Sioux on. This is gonna give minus three minus two zero one zero minus two minus 6 14 And then When you do this, you&#x27;re gonna out 0000 so we can see that. Look at this. Look at this. So we can see that this is Constance is consistent. So we see Dr the documented metrics. The augmented metrics correspond. So a consistent system through a consistent system. So this implies that P is in colon off, eh?

Fan Yang · Answer

a be equal importance off A B means chicks, eh? Terms tragic be so the calculus function will be two minus 34 minors to like 23 past 12. Negative six past eight. And there&#x27;s a final and so welcome Get till one two No. Two And therefore the B A B is the products off B and es at length. So we were down the magics be first and there&#x27;s a right down the magics, eh? To notice one pill story for and, uh, the calculated it. So, um, you know it will be to minor six negative one class eight takes minor six active three plus eight. And there&#x27;s a final answer. Well, be doctor for 705 So this cheery about Nico all this today So it&#x27;s a means a B not seek orchard B a.

Julie Silva · Answer

we&#x27;re being asked if 12 satisfies to given equation. Well, that means when we substitute 12 in Place X, it will create a true statement. So let&#x27;s see if it works. So when we substitute 12 in Forex, we&#x27;re gonna have 1/2 times 12 minus four and we want to know. Is that equal to one? Third times 12 minus two? Well, 1/2 times 12. This six. We have six minus four and 1/3 times 12 is four. So we have four minus two. Well, six Find this force to and four minus two is two. Therefore, we found that when we substitute 12 and for X, we get a true statement. Therefore, answer is yes, the number 12 satisfies to given equation.

Fan Yang · Answer

full caution. A. We&#x27;re looking for the products off a P. So it&#x27;s how well be so First of all, we write downs and magics One birth, because there&#x27;s a one shoe one would and then right down the magics be This is the are free when you chew and, uh, we calculate it is well be one times zero class, two times one and there one time three purse two times two The secondary role. I&#x27;ll be one tons, zero class, one ton street and there won times Oh, sorry. It&#x27;s a secular Oh, well, Giza when part one times Verapaz won tons work and they&#x27;re one town story plus one times two. So the s around B zero plus two and a straight class four three pass to the aura past one and it&#x27;s the final lesson will be to sever 45 for the problem. Be way looking for so a green, you see? So first of all, we got to the answer off a peon there for either question A. The answer is true. 715 And then we&#x27;d write down the magic. See, Is the world like your four? Well, one tender we calculated by the same way. It&#x27;s a true times weren&#x27;t past seven times one and UH, two times nicked in four plus seven time for for the second row is a worm password. One times weren&#x27;t wasthe. First time swarm and the one times 9 to 4 past five times one shows. Answer. Wealthy to past seven Thank you eight past seven and thus far looked in school class fired and as a final after while being my don&#x27;t have word sex and aware for the question, See, really look youthful, We&#x27;re looking for a plastic be How is she the products off a plus B in the sea? So first of all, we calculates the A plus B. It&#x27;s a world be what your guns are. Magic. So a first and the class is a magic speak and the answer will be 15 truths Rick. And then we can calculate birth Charles who? Well, the paradox awful. A Cosby and the Sea. It&#x27;s a will being re first writes down the ass off a poss B from sir to risk me and it happens magics and see if one elected for or one Phil. We do the same thing as we&#x27;re in class one when Time for class, five times a one and, uh, word times next four plus fun times. Well, and the two times were class three times World two times 9 to 4 Clause three times one fan, sir. Calculate it as no up you. One plus five victim full crossed. Five true pasts re elected eighth class three and the final as well be 615 may be terrified.

Coach Rye · Answer

if negative too is a solution to this he set. So what? That means that I&#x27;m a plug in negative to four X. That means I have negative 1/2 minus 1/2 negative. Negative. You add, Which gives you a negative one and does negative one equal negative one? Yes, it does. So that one is a solution.

Problem

Let $\mathbf{v}_{1}=\left[\begin{array}{r}{2} \\ …

Problem 5 Easy Difficulty

Answer

$p _ { 1 } \notin \operatorname { conv } ( S )$ and $p _ { 2 } \in \operatorname { conv } S$

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David C. Lay, Steven R. Lay, Judi J. McDonald

Linear Algebra and Its Applications

Catherine R.

Anna Marie V.

Samuel H.

Michael J.

Vectors Intro

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$p _ { 1 } \notin \operatorname { conv } ( S )$ and $p _ { 2 } \in \operatorname { conv } S$

Linear Algebra and Its Applications

Catherine R.

Anna Marie V.

Samuel H.

Michael J.

Vectors Intro

Vector Basics - Example 1

David C. Lay, Steven R. Lay, Judi J. McDonaldLinear Algebra and Its Applications

Catherine R.

Anna Marie V.

Samuel H.

Michael J.

David C. Lay, Steven R. Lay, Judi J. McDonald

Linear Algebra and Its Applications