00:01
Okay, this question wants us to find the distance between these two vectors.
00:07
So to do this, we need to notice that the shortest path between any two vectors is the perpendicular distance between them.
00:16
So what we're looking for is the magnitude of the perpendicular component.
00:21
So to do this, we'll first find the parallel component, and i'll say that the parallel of y that's in the same direction as you is just the projection onto u of y, which would be y.
00:41
Y.
00:41
U over the magnitude of u squared times u.
00:49
So filling in the relevant numbers here, y.
00:52
Dot u would be 8 times 3 is 24 plus 1 times 6, which is 6.
01:03
And then we divide by the magnitude of u squared, which is 8 squared plus 6 squared, and then we distribute that into our vector u, which is still 8 ,6...