Question
Let $\mathbf{z}=\mathbf{x}+\mathrm{i} \mathbf{y} \in \mathbb{C}^n$.(a) Prove that, for the Hermitian dot product, $\|\mathbf{z}\|^2=\|\mathbf{x}\|^2+\|\mathbf{y}\|^2$.(b) Does this formula remain valid under a more general Hermitian inner product on $\mathbb{C}^n$ ?
Step 1
Step 1: Define the Hermitian dot product for vectors $\mathbf{u}, \mathbf{v} \in \mathbb{C}^n$ as $\langle \mathbf{u}, \mathbf{v} \rangle = \sum_{j=1}^n u_j \overline{v_j}$, where $\overline{v_j}$ denotes the complex conjugate of $v_j$. Show more…
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