Let $\otimes$ be an associative binary operation on a set $S$. For example, $\otimes$ could be: + on $N a t, \times$ on $R e, \wedge$ or $\vee$ on $S C$ sentences, functional composition, or any group operation. Since $\otimes$ is associative, for any $x, y, z \in S$,
$$
x \otimes(y \otimes z)=(x \otimes y) \otimes z .
$$
The identity sign means that the value of the left side of the equation is the same as the value of the right side, for any input values $x, y, z$. If we have an operation on numbers, then the number denoted by the left side is the same as the number denoted by the right side. If we have an operation on a group, then the group element denoted by the left side is the same as the group element referred to by the right side. If we are considering $\wedge$ or $\vee$ on $S C$ sentences, then the truth value of the left side (under an interpretation) is the same as the truth value of the right side (this amounts to tautological equivalence). These instances should clarify what is meant by the preceding equation. We now introduce abbreviated notation: For $n \in N a t$,
$$
\begin{aligned}
& x_1 \otimes \cdots \otimes x_{0+1}=x_1, \\
& \text { and } \\
& x_1 \otimes \cdots \otimes x_{n+1}=\left(x_1 \otimes \cdots \otimes x_n\right) \otimes x_{n+1} .
\end{aligned}
$$
This is just a recursive definition for the three-dot notation (ellipsis) in this context. Let $n \geq 3$ and prove that, for $1 \leq k<k+1 \leq n$,
$$
\left(x_1 \otimes \cdots \otimes x_k\right) \otimes\left(x_{k+1} \otimes \cdots \otimes x_n\right)=x_1 \otimes \cdots \otimes x_n .
$$
[Remark. This result is a simple generalization of association. A stronger generalization can be proved for arbitrary associative combinations.]