Question
Let $p$ be prime. If the order of every element of a finite group $G$ is a power of $p$, prove that $|G|$ is a power of $p$.
Step 1
First, we recall the definition of the order of an element: The order of an element $g$ in a group $G$ is the smallest positive integer $n$ such that $g^n = e$, where $e$ is the identity element of the group. Show more…
Show all steps
Your feedback will help us improve your experience
Brandon Collins and 55 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Suppose that $G$ is a finite Abelian group. Prove that $G$ has order $p^{n}$, where $p$ is prime, if and only if the order of every element of $G$ is a power of $p$.
If the order of $G$ is even, there is at least one element $x$ in $G$ such that $x \neq e$ and $x=x^{-1}$ In parts 4 to 6, let $G$ be a finite abelian group, say, $G=\left\{e, a_{1}, a_{2}, \ldots, a_{n}\right\} .$ Prove: $$
ELEMENTARY PROPERTIES OF GROUPS
E
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD