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Hello.
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So here in part a, we consider the following plane where we have x plus y plus 2z is equal to zero, and the vector b here is equal to 311.
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Now, we're going to find an ortho -normal basis for the plane here for p.
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So here we have that v1 and v2 are elements of p.
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So a normal vector to the plane is going to be the normal vector.
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The normal vector.
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Here is going to be equal to 112.
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We just use the coefficients of x, y, and z in our plane equation.
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Now, since the vector n here is orthogonal to v1, the dot product of v1 and n is going to be zero.
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Therefore, we have that v1 dotted with 112 is equal to zero.
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We then use the result.
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The vector v1 can then be taken as 1 negative 1 .0.
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So then we can use that 1 -0 dotted with 1 -1 -2 is going to be equal to 0.
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Now the vector v2 can then be taken by the cross product.
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So v2 is going to be equal to n cross -v1.
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So that is equal to while we use the ijk here, right? and then we set up a matrix.
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We say 1, 1, 2, 1, negative 1, 0...