Let $P Q$ and $R S$ be tangents at the extremities of the diameter PR of a circle of radius $r .$ If $P S$ and $R Q$ intersect at a point $X$ on the circumference of the circle, then $2 r$ equals
(a) $\sqrt{P Q \cdot R S}$
(b) $(P Q+R S) / 2$
(c) $2 P Q \cdot R S /(P Q+R S)$
(d) $\sqrt{\left(P Q^{2}+R S^{2}\right)} / 2$