00:01
So they ask us to let up that pb your point on a plane and with the normal vector and a cubic point off the plane.
00:10
And i show that the distance between d, the distance d between the point in the plane can be expressed like this.
00:19
And they give us a problem to do using that.
00:25
So what i did is i just started trying to draw this in three dimensions.
00:28
You can always figure out a direction to look down so that your plane is basically looks like a line.
00:36
And then we'll have a point off that plane.
00:40
And so looking down that direction, it kind of becomes a 2d problem.
00:45
And so you can see, look at it a little better.
00:48
Now we have, we want this distance here, so that this is perpendicular.
00:54
So we have a point on the, we can find a point on the plane.
00:57
So we can just plug in, just find any point on this plane.
01:03
And then we're given some point off the plane.
01:06
And so we want to find this distance so that this line is perpendicular here.
01:12
Well, we can do that by noting that defining this angle here, that this distance is the length of this factor times the cosine of this angle...