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Let POS stand for a positive number and NEG stand for a negative number. Determine the sign of each result, if possible.a. $\mathrm{NEG} \cdot \mathrm{NEG}$b. $\mathrm{NEG}+\mathrm{NEG}$c. $\mathrm{NEG}-\mathrm{NEG}$d. $\frac{\mathrm{NEG}}{\mathrm{NEG}}$
a. $\ \mathrm{NEG}^{*} \mathrm{NEG}=\mathrm{POS}$b.NEG+NEG=NEGc.NEG-NEG=NOT POSSIBLE(Depends on the value of numbers.If both are same the and is $0 .)$d. $\frac{N E G}{N E G}=P O S$
Algebra
Chapter 1
An Introduction to Algebra
Section 6
Multiplying and Dividing Real Numbers; Multiplication and Division Properties
The Language of Algebra
Equations and Inequalities
Functions
Linear Functions
Quadratic Functions
Polynomials
Oregon State University
University of Michigan - Ann Arbor
Idaho State University
Lectures
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Let POS stand for a positi…
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gives us combinations of positive negative and once is to try to find the sign of the result, if possible. So for part A, we have negative times Negative, because the signs of the same we're gonna get positive. Part beam. We have negative plus negative. Okay. And now you're number. We make it a bigger negative number. Still gonna be negative part. See, we have negative subtracting and negative In this case, we do not know if it'll be positive or negative because we don't know the size of that second value. Andy, we have negative divided by negative. Because these signs are the same, we will get a positive value.
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