Question
Let $P=(s, t)$ be a point in the $x y$ -plane. Let $P^{\prime}=(t, s)$. Calculate the slope of the line $\ell^{\prime}$ that passes through $P$ and $P^{\prime} .$ Deduce that $\ell^{\prime}$ is perpendicular to the line $\ell$ whose equation is $y=x$. Let $Q$ be the point of intersection of $\ell$ and $\ell^{\prime}$. Show that $P$ and $\ell^{\prime}$ are equidistant from $Q$. (As a result, each of $P$ and $P^{\prime}$ is the reflection of the other through the line $y=x .)$
Step 1
The slope of a line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the formula $\frac{y_2 - y_1}{x_2 - x_1}$. Here, $P=(s, t)$ and $P^{\prime}=(t, s)$, so the slope of $\ell^{\prime}$ is $\frac{s - t}{t - s}$. Show more…
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Let $P=(s, t)$ be a point in the $x y$ -plane. Let $P^{\prime}=(t, s)$ Calculate the slope of the line $\ell^{\prime}$ that passes through $P$ and $P^{\prime}$ Deduce that $\ell^{\prime}$ is perpendicular to the line $\ell$ whose equation is $y=x .$ Let $Q$ be the point of intersection of $\ell$ and $\ell^{\prime}$ Show that $P$ and $P^{\prime}$ are equidistant from $Q$. (As a result, $P$ and $P^{\prime}$ are reflections of each other through the line $y=x$
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