00:01
And this problem, we must prove that matrix a is nil potent by raising it to sum power p and resulting in a zero matrix.
00:09
So we will begin by multiplying matrix a by itself.
00:17
In other words, raising it to the second power.
00:21
So i'll write this out.
00:23
As you can see, there are already a lot of zeros.
00:27
So a lot of our math will result in zeros.
00:30
Again, in matrix math, we'll start with the first column and multiply by the first row.
00:39
I think it's a 0 times 0 plus 0 times 0 plus 0 times 1 is 0.
00:51
This will result in a 3 by 3 matrix, with that being the first step.
00:59
And as we continue forward, we will also have the next row.
01:10
Three zeros, but this row results in a one times one.
01:15
So we do have a one there...