00:01
We want to prove that this function is continuous at 0 .0.
00:04
So for it to be continuous, we want to show that its input is equal to its limit.
00:12
All right.
00:12
So at f of 0, well, this is a case of when x times y is equal to 0.
00:21
So we'd fall into this.
00:23
So we would have natural log of 2.
00:25
So we want to show that the limit of this is equal to natural log of 2.
00:32
So let's see what we have.
00:35
So we're going to have the limit as x, y, approaches 0, 0.
00:43
And we really only want to show that this limit approaches natural log of 2, because in the denominator, since both of these are 0, it would be 0.
00:53
So let's go ahead and have that there.
00:57
So we would have 2x minus 1 over xy sine of y.
01:07
Now notice that we can go ahead and break this up into two separate ones like so.
01:15
So we could have one where it's the limit as x approaches 0 of 2x minus 1 over x times the limit as y approaches 0 of sine of y over y...