00:01
For exercise 107, we have for this exercise, for our first case, we have, for this exercise, for our first case, we have that xp, open parentheses, and minus one, close parentheses, s squared, sub 1, plus open parentheses, and minus 1, plus, open parentheses, and minus 1, close parentheses, s squared sub 2, close parentheses, times open parentheses 1 divided by 2 sigma squared sub a minus 1 divided by 2 sigma squared sub 0 close parentheses is less than k and we find that n minus 1 close parentheses s of 1 squared plus open parentheses n minus 1 close parentheses s squared sub 2 is greater than k for some constant okay and then for case 2 we can say that l omega is equal to 1 to, and i'm going to write this down here, 1 divided by the root of 2 pi, sigma to the power of n plus n, that's in parentheses, times exp, open parentheses, negative sigma i equals 1 to n, open parentheses, y sub i minus y bar, close parentheses, square divided by 2, sigma squared, 0, close parentheses, times exp, open parentheses, negative sigma, j equals 1 to m, open parentheses, x of j minus x bar, close parentheses squared, divided by 2 sigma squared sub 0.
02:33
Close parentheses is equal to l omega sub 0...