00:01
Hi, so for this exercise, we need to find a matrix for the transformation of t by the given basic vectors.
00:08
That are t, t, 1, t2.
00:12
We, by knowing that, we can start by finding the images of each one of them after their linear mapping in t.
00:22
So we start by t1 equals to t.
00:38
It's going to have a multiply by the basic vectors that is 1, t, and t2.
00:53
Because of we're looking, sorry, so we are looking for t1.
01:01
Our values are going to be centered on 1.
01:08
So 1 is going to be 1.
01:12
T is going to be 0.
01:15
And t2 is going to be also zero and these values we can change them to a -0, a1, and a2.
01:38
So in our general equation, we're going to be subdividing each one of them for the finding of the linear mapping.
01:53
So we start by 3a0.
01:57
We have the value that is 1.
02:01
So we write here 1 plus we have here 5 .0.
02:11
So 5 is also going to be multiplied by 1.
02:15
But then we have minus 2 .1.
02:20
Minus 2a1.
02:22
So minus 2.
02:24
We have the value of a1 that is 0.
02:28
So we write that 2 is multiplied by 0.
02:33
Later we write here that they have t.
02:39
It is right here.
02:43
Then we put plus for a1 that we have.
02:53
For a1, a1 has the value of 0.
02:57
So 4 multiplied by 0 plus a2 that also has a value of 0.
03:06
So we write here 0.
03:11
We close it and we write t2.
03:22
Now we go.
03:24
3 stays the same, so it's 3.
03:28
Here we have 5 minus 2.
03:38
That is 0.
03:41
So here we write 5, but it's multiplied by t, so it's 5t.
03:49
Here we have 0 and 0 also here, so this is going to be multiplied by 0.
03:59
So this is going to be 0 2.
04:09
In linear mapping, this is writing like 3, 5, and 0.
04:24
That's our first column.
04:28
So we go for our second that we're now going to use the t, t1, t, sorry...