In this case, the PDF is given by $f(y) = \frac{2}{\pi(1+y^2)}$ for $-1 \leq y \leq 1$ and $0$ elsewhere. Therefore, we can write the CDF as:
$$
F(y)=\int_{-\infty}^{y} f(x) dx
$$
However, since $f(x)$ is $0$ for $x < -1$ and $x > 1$, we can simplify the integral
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