Let the function $f$ be defined as $f(x)=\left\{\begin{aligned} \frac{P(x)}{x-2}, & x \neq 2 \\ 7, & x=2 \end{aligned}\right.$
where $P(x)$ is a polynomial such that $P^{\prime \prime \prime}(x)$ is identically equal to 0 and $P(3)=9 .$ If $f(x)$ is continuous at $x=2$, then
(A) $P(x)=2 x^{2}-x-6$
(B) $P(x)=2 x^{2}+x-6$
(C) $P(x)=2 x^{2}-x+6$
(D) None of these