00:01
In this exercise, we're given two matrices, a and b, which are both square matrices, and what we know is that the product, a times b, is an invertible matrix.
00:12
Our goal here is to show a inverse exists from this given information.
00:21
Well, this can be a tricky problem, but what's going to help us is using the definition of what it means to be invertible.
00:28
So, since a times b is invertible, there...
00:32
Exists.
00:36
An n -by -n matrix, let's call it c such that the product a times b times this matrix c is the identity matrix.
00:52
So this is strictly by the definition of what it means to be invertible, but recall our goal is to show a inverse exists.
01:01
To that end, let's use our most powerful tool in the shed, the invertible matrix theorem.
01:06
But let's place it also in a respectable spot.
01:09
There we go...