Question
Let $X$ be a binomial random variable with prob ability distribution $$f(x)=\left\{\begin{array}{l}\left(\begin{array}{l}3 \\x\end{array}\right)\left(\frac{2}{5}\right)^{x}\left(\frac{3}{5}\right)^{3-x} \\0\end{array}\right.$$ $$x=0,1,2,3$$ Find the probability distribution of the random variable $Y=X^{2}$.
Step 1
Since $Y = X^2$ and $X$ can take the values 0, 1, 2, 3, the possible values of $Y$ are 0, 1, 4, 9. Show more…
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