00:01
Hi guys, in this problem we are given that x is a random variable that takes values between 0 and c.
00:06
So we know that probability of x where x more than or equal 0 and less than or equal to c is equal to 1.
00:16
Okay, that means x x more than or equal 0 and less than or equal c.
00:25
This implies that x squared is less than or equal cx okay so from this equality we get the mean of x squared is less than or equal the mean of c x so the mean of x squared this is less than or equal x times the mean of x okay so here we have the mean of x squared minus the mean of x whole squared less than or equal c times the mean of x minus the mean of x all squared okay, so this is the value of the variance of x.
01:24
Okay, unless zan or equal e of x is a common factor times c minus e of x.
01:36
Okay, now we can find that alpha is equal to the mean of x over c.
01:47
This implies that the mean of x is equal to c times alfx.
01:53
Okay so we have the variance of x less than or equals mean of x times c minus is the mean of x okay so this implies that variance of x and less than or equal c a or c a or c alpha times c minus c alpha so the variance of x can be rewritten as c squared times alpha times one minus alpha okay since we have x more than or equal zero and less than or equal c which implies that the mean of x is more than or equal zero and less than or equal c so if we divide it over c, we have the mean of x over alpha is more than or equal 0 and less than or equal.
03:13
I'm sorry, we will divide over c...