Question
Let $X$ have the pdf $f(x)=2 x, 0<x<1$, zero elsewhere. Compute the probability that $X$ is at least $\frac{3}{4}$ given that $X$ is at least $\frac{1}{2}$.
Step 1
This can be written as $P(X \geq \frac{3}{4} | X \geq \frac{1}{2})$. Show more…
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Let $X$ have the pdf $f(x)=2 x, 0<x<1$, zero elsewhere. Compute the probability that $X$ is at least $frac{3}{4}$ given that $X$ is at least $frac{1}{2}$.
Let $f(x)=\frac{1}{3},-1<x<2$, zero elsewhere, be the pdf of $X$. Find the cdf and the pdf of $Y=X^{2}$. Hint: Consider $P\left(X^{2} \leq y\right)$ for two cases: $0 \leq y<\mathbb{1}$ and $1 \leq y<4$.
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