Let $X_{1}, X_{2}, \ldots, X_{n}$ be independent and identically distributed exponential random variables. Show that the probability that the largest of them is greater than the sum of the others is $n / 2^{n-1}$. That is, if
$$
M=\max _{j} X_{j}
$$
then show
$$
P\left\{M>\sum_{i=1}^{n} X_{i}-M\right\}=\frac{n}{2^{n-1}}
$$
Hint: What is $P\left[X_{1}>\sum_{i=2}^{n} X_{i}\right\} ?$