Let $X_{1}, X_{2}, \ldots, X_{n}$ denote a random sample from a Poisson distribution with parameter $\theta>0$. From Remark 7.6.1, we know that $E\left[(-1)^{X_{1}}\right]=e^{-2 \theta}$.
(a) Show that $E\left[(-1)^{X_{1}} \mid Y_{1}=y_{1}\right]=(1-2 / n)^{y_{1}}$, where $Y_{1}=X_{1}+X_{2}+\cdots+X_{n}$.
Hint: First show that the conditional pdf of $X_{1}, X_{2}, \ldots, X_{n-1}$, given $Y_{1}=y_{1}$, is multinomial, and hence that of $X_{1}$, given $Y_{1}=y_{1}$, is $b\left(y_{1}, 1 / n\right)$.
(b) Show that the mle of $e^{-2 \theta}$ is $e^{-2 \bar{X}}$.
(c) Since $y_{1}=n \bar{x}$, show that $(1-2 / n)^{y_{1}}$ is approximately equal to $e^{-2 \pi}$ when $n$ is large.