Let $X_{1}, X_{2}, \ldots, X_{n}$ denote a random sample of size $n>1$ from a distribution with pdf $f(x ; \theta)=\theta e^{-\theta x}, 0<x<\infty$, zero elsewhere, and $\theta>0 .$ Then $Y=\sum_{1}^{n} X_{i}$ is a sufficient statistic for $\theta$. Prove that $(n-1) / Y$ is the MVUE of $\theta$.