Specifically, for any $0 \leq s < t$, the increment $X(t) - X(s)$ is normally distributed with mean $\mu(t-s)$ and variance $\sigma^2(t-s)$.
Now, let's consider the joint distribution of $X(s)$ and $X(t)$. We can write $X(t)$ as the sum of two increments: $X(t)
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