Question
Let $y(t)$ be a solution of $(\cos y+1) \frac{d y}{d t}=2 t$ such that $y(2)=0$.Show that $\sin y+y=t^{2}+C .$ We cannot solve for $y$ as a function of $t,$ but, assuming that $y(2)=0,$ find the values of $t$ at which $y(t)=\pi$.
Step 1
We can rewrite this as $\frac{d y}{d t}=\frac{2 t}{\cos y+1}$. Show more…
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