Question
Light containing two different wavelengths passes through a diffraction grating with $1.20 \times 10^{3}$ slits/ $\mathrm{cm} .$ On a screen 15.0 $\mathrm{cm}$ from the grating, the third-order maximum of the shorter wavelength falls midway between the central maximum and the first side maximum for the longer wavelength. If the neighboring maxima of the longer wavelength are 8.44 $\mathrm{mm}$ apart on the screen, what are the wavelengths in the light? Hint: Use the small-angle approximation.
Step 1
This is given by the inverse of the number of slits per centimeter, which is $1.20 \times 10^{3}$ slits/cm. Therefore, we have \[d = \frac{1}{1.20 \times 10^{3} \, \text{slits/cm}} = 8.33 \times 10^{-6} \, \text{meters}.\] Show more…
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