00:01
For this problem on the topic of geometric optics, we are told that light is passing from a into flint glass, and we want to know the angle of incidence that will allow the component of its velocity perpendicular to the interface to remain constant.
00:15
We then want to know if the component of velocity parallel to the interface can remain constant during refraction.
00:23
Now, refraction proceeds according to snell's law, where one times the sign of the...
00:32
Angle of incidence theta 1 is equal to the refractive index of flint glass 1 .66 times the sign of angle theta 2 where theta 2 is the angle of refraction we'll call this equation number 1 now for the normal component of velocity to be constant we need v1 cosine theta 1 to equal to v2 cosine theta 2 or for light c cosine theta 1 equal to c over 1 .66 cosine theta 2.
01:19
We'll call this equation 2.
01:21
If we multiply equations 1 and 2, we get sine theta 1, cosine theta 1 is equal to sine theta 2, or 2 -sign, rather sign of 2 -the -1, is equal to sine of 2 -theta -2.
02:00
Now the solution, theta -1 is equal to theta -2 is equal to 0, does not satisfy equation 2 and has to be rejected...