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Light travels a distance of 0.902 $\mathrm{m}$ in 4.00 $\mathrm{ns}$ in a given substance. What is the index of refraction of this substance?

Hence, the index of refraction of the substance is $[1.33]$

Physics 103

Chapter 26

Geometrical Optics

Wave Optics

Cornell University

University of Washington

Hope College

McMaster University

Lectures

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All right. So this problem we're seeing the ray of light traveling through a certain substance travels the distance of 0.902 meters in time of four times 10 minutes, nine seconds or four nanoseconds and wondering what is the index of refraction of light within this material is traveling through. So first need to find speed of of like that as traveling through this substance. So the velocity of light is gonna be equal to, well, just this displacement divided by time to your 0.90 to talk about changing time four times 10 the native nights, we're just going to be equal to 2.2 55 times 10 to the eighth. That is the velocity of light. As it's traveling through this new medium and order find the index of a fraction end. We're just gonna take that velocity of light and have it be and divide the speed of light in a vacuum by velocity. So take C and divided by Visa Bell. We're say the speed of light in a vacuum is just three times 10 80. Divide that by 2.255 times 78th. We should get an index of refraction of 1.33

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