00:01
So the light of the wave of 425 nanometers falls on a potassium surface, and what we see is electrons ejected at a given speed.
00:07
So the total energy of the incident light is the sum of the energy needed for the ejection of the electrons and the kinetic energy of the ejected electrons.
00:17
So firstly, we'll take a look at the kinetic energy, where kinetic energy, k -e, is equal to 1 over 2 mv squared.
00:30
So we can calculate this and get 1 .1 times 10 to the minus 19 joules.
00:39
Next we can look at the energy that is equal to planck's constant multiplied by the frequency.
00:46
Why the energy is equal to 4 .7 times 10 to the minus 19 joules.
00:54
So the total energy of the instant light, we can look at next.
01:02
So we have the kinetic energy of the ejected electrons, 1 .1 times 10 to the minus 19 joules...