00:01
For this problem on the topic of geometric optics, we are told that light, which has a wavelength of 700 nanometers, is incident on the face of a fused quartz prism at an angle of 75 degrees with respect to the normal of that surface.
00:13
The apex angle of the prism is 60 degrees, and using the value of n from the given figure, we want to calculate the angle of refraction at the first surface, the angle of incidence at the second surface, the angle of refraction at the second surface, and the angle between the incident and emergent rays.
00:37
Now we know the refractive index at 700 nanometers is 1 .440.
00:45
So firstly from snell's law we have 1 times the sign of the incident angle 75 degrees is equal to 1 .458 times the sign of theta 2.
01:05
And we want to solve for theta 2, so rearranging we get theta 2 to be 41 .5 degrees.
01:14
For part b, we want to find angle theta 3.
01:24
Now we know angle theta 3 plus angle beta is equal to 90 degrees.
01:37
And theta 2 plus alpha is also equal to 90 degrees.
01:47
And alpha plus beta plus 60 degrees is equal to 180 degrees...