Question
Light with an energy flux of $18 \mathrm{w} / \mathrm{m}^{2}$ or $\mathrm{Wm}^{-2}$ falls on a non-reflecting surface at normal to surface. If the surface has an area of $20 \mathrm{~m}^{2}$. The average force exerted on the surface during 30 minutes is(A) $6.48 \times 10^{5} \mathrm{~N}$(B) $3.60 \times 10^{2} \mathrm{~N}$(C) $1.2 \times 10^{-6} \mathrm{~N}$(D) $2.16 \times 10^{-3} \mathrm{~N}$
Step 1
The momentum of a photon is given by its energy divided by the speed of light, $c$. Therefore, the force exerted by light on a surface is given by the rate of change of energy, which is power, divided by the speed of light. Show more…
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"Light with an energy flux of 18 W cm–2 falls on a non-reflecting surface at normal incidence. If the surface has an area of 20 cm2, the average force exerted on the surface during a 30 minute time span is (a) 2.1 × 10–6 N (b) 1.2 × 10–6 N (c) 1.2 × 106 N (d) 2.1 × 106 N"
Light with an energy flux of 18w/cm2 falls on a non-reflecting surface at normal incidence. If the surface has an area of 20cm2. Find the average force exerted on the surface during a 30 minute time span.
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