00:01
So, here we have the limit.
00:04
X goes to negative 1, x to 3, minus x square, minus 5x minus 3, over x to the 4th plus 2, x to the 3, minus x squared minus 4 x minus 2.
00:20
So, if we just plug in a negative 1 for the x values, we get 0 over 0.
00:26
So we can use lopidol's rule because we have zero over zero.
00:32
So the limit is x goes to negative one.
00:41
The derivative of the top, 3x square minus 2x, minus 5, over the derivative of the bottom, 4x q plus 3x, 6x square, i mean, minus 2x...