00:03
We're told that liquid a has a vapor pressure equal to x, and liquid b has a vapor pressure equal to y.
00:18
So what is the mole fraction of the liquid mixture if the vapor pressure above the solution is 30 % by moles? so the mole fraction of a plus the mole fraction of b is equal to 1, and then we can apply relative's law.
00:32
The partial pressure of a plus the partial pressure of a plus the partial pressure of b is equal to 1.
00:45
Not equal to 1, sorry, times 100 is equal to 30.
00:50
So that would be our 30%.
00:53
And now we can substitute these variables into this equation here.
01:00
Rearranging, i'll get 0 .30 is equal to the mole fraction of, a times x over the mole fraction of a times x plus the mole fraction of b times y and substituting mo fraction of a times x mole fraction of a times x plus one minus the mole fraction of a plus 0 .30y minus 0 .30 mole fraction of a is equal to the mole fraction of a times x and the mole fraction of a would be equal to 0 .30y over 0 .70x plus 0 .30y and here is our mole fraction of and this would be at 30 % a bimoles.
02:17
In a very similar way, if the vapor pressure is 50 % a, so 50 % a bimoles, the mole fraction of a is equal to y over x plus y and the mole fraction of b would be equal to 1 minus y over x plus y and if we have 80 % a bimals the mole fraction of a is equal to 0 .80y is equal to 0 .80 y over 0 .80x plus 1 .1 and the mole fraction of b is equal to 1 minus 0 .80y over 0 .20x plus 0 .80y.
03:44
If we in the second half we're looking at the mole fraction of the vapor above the solution, so the vapor above the solution, this would be, so the mole fraction of the vapor of the vapor above the solution.
04:12
Mor fraction a vapor is equal to p .a...