00:01
All right, so we're told that liquid methanol reacts with oxygen, and we're given the amount of heat that is liberated.
00:08
We're first told to write the equation of that reaction, and to include the heat of the reaction.
00:17
So basically we have ch3oh, which is emitted as plus oxygen gas, and would have co2 and water.
00:32
If you balance, you see that this should be two, right? so this is going to be four, this is also going to be two, and this will be three.
00:43
So this is balanced.
00:44
Now the delta h of this reaction is, it is liberated, it's a combustion reaction, which tells you that the reaction produces 363 kilojoules per mole.
01:00
But you see that this equation, right? there are two moles of methanol.
01:05
So the heat of this reaction is twice of that.
01:09
That's it.
01:10
The heat of this reaction is twice of that, three times two of that.
01:16
So actually, the heat of this reaction is going to be 726 kilojoules.
01:23
Now if we're to write this equation to include that, so because it's a combustion reaction, and it's exothermic, i've answered one of the questions already.
01:30
So this is 2oh plus three moles of o2 to give us two moles of co2 plus four moles of water, and then we add 726 kilojoules.
01:44
This would be the equation of the reaction, right? and you can see that the heat produced is on the product side.
01:52
And i said, because the equation has two moles of methanol, that's why we have that to be the heat of the reaction.
02:03
And the second part says, is it endo or exo? it is exothermic.
02:06
Combustion reactions are exothermic reactions...