00:01
Okay, so for this problem, part a and part b, they are kind of like the same.
00:06
But we need to make an assumption that the second order derivative at the center a is non -zero.
00:16
So we need to make this assumption here.
00:20
So both a and b are true under this assumption.
00:23
Because if we have this assumption, the second -order telary polynomial is equal to f of a.
00:32
Plus f prime of a times x minus a plus one half times the second of the derivative at a times x minus a square so if f has a local maximum at x equals to a that means f prime of a equals to zero and the second order derivative is less than 0.
01:04
So basically we are looking for p2x equals to f of a plus one half f double prime of a times x minus a square.
01:14
Since f double prime of a is less than zero, if we graph p2 x on a coordinate system, so it looks like this, and it will achieve a local maximum at this point a.
01:29
So for the same reason, if f2x, if f has a local minimum, so is p to x.
01:38
As for c is not correct...