Question
Locate the absolute extrema of the function on the closed interval.$$f(x)=2(3-x),[-1,2]$$
Step 1
Step 1: First, we expand the brackets in the function $f(x)=2(3-x)$ to get $f(x)=6-2x$. Show more…
Show all steps
Your feedback will help us improve your experience
Lucas Finney and 98 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the absolute extrema of the function on the closed interval. $$f(x)=3-x,[-1,2]$$
Applications of Differentiation
Extrema on an Interval
Locate the absolute extrema of the function on the closed interval. $f(x)=x^{3}-\frac{3}{2} x^{2},[-1,2]$$
Find the absolute extrema of the function on the closed interval. $$f(x)=x^{3}-\frac{3}{2} x^{2},[-1,2]$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD