00:01
In this first problem, in this first part of the problem, we have to find the potential drop across each of these two resistors.
00:09
We're given a straight line and we know that at point a, the potential is 24 volts.
00:16
And also the current is going to be two amps, but that current is going to be constant throughout the entire wire because the two resistors are connected in series.
00:27
So let's use olm's law to find the potential drops.
00:31
Let's begin with this resistor and call it r1.
00:36
The oms law states that the potential difference is going to be equal to the current times the resistance.
00:48
And in this case, we already have all the information we need.
00:52
We have the 2 amps times the 4 oms, and that gives us 8 volts.
01:00
Let's go to the second resistor.
01:04
We have the same.
01:06
The current times resistance.
01:13
The current, as we said, is the same, so we have the same 2 amps times the resistance, which is 6.
01:23
That gives us 12 volts.
01:27
Now let's move on to part b.
01:30
In part b, we are being asked to find the potential at each of these points in the line, a, b, c and d.
01:37
We already know the potential for a...