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Look at the graph for a diode in Figure 29.23$( \mathrm { b } )$ in the text. Why does this graph go below the horizontal axis to the left of the origin? Would it do this if the diode were replaced by an ordinary resistor?

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Physics 103

Chapter 29

Atoms, Molecules, and Solids

Atomic Physics

Nuclear Physics

University of Washington

Hope College

University of Winnipeg

Lectures

02:42

Atomic physics is the field of physics that studies atoms as an isolated system of electrons and an atomic nucleus. It is primarily concerned with the arrangement of electrons around the nucleus and the processes by which these arrangements change. The theory of quantum mechanics, a set of mathematical rules that describe the behaviour of matter and its interactions, provides a good model for the description of atomic structure and properties.

02:26

In physics, nuclear physics is the field of physics that studies the constituents and interactions of atomic nuclei. The most commonly known applications of nuclear physics are nuclear power generation and nuclear weapons technology, but the research has provided application in many fields, including those in nuclear medicine and magnetic resonance imaging, ion implantation in materials engineering, and radiocarbon dating in geology and archaeology.

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for a question 24. Look closely at the graph in the text as the problem asked, and we want to ask ourselves, Why does it go below the horizontal axis to the left for the origin? So if I draw an example dialled graph year I V, it might look something like this. So it does saturate at some value here. It doesn't just blow up in the native direction, but ah, there is some negative current in the reverse direction if the applied voltage is in the reverse direction. So reverse biased though there is a current limit and that is the whole benefit to using dye odes because it limits the back current that you'll get. And if we wantto think about thie ordinary resistor, which I will put in red, then it is actually this dotted line case because unordinary resistor is just these equal to ay are so you have a linear relationship between current and voltage. So yes, if you have a negative voltage than you having negative current as well

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