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Look up the $K_{\mathrm{sp}}$ values for $\mathrm{BaSO}_{4}$ and $\mathrm{SrSO}_{4}$ in Table 16.2. Calculate the concentrations of $\mathrm{Ba}^{2+}$ $\mathrm{Sr}^{2+},$ and $\mathrm{SO}_{4}^{2-}$ in a solution that is saturated with both compounds.

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$$=18 \times 10^{-7} \mathrm{M}$$

Chemistry 102

Chapter 16

Acid-Base Equilibria and Solubility Equilibria

Acid-Base Equilibria

Aqueous Equilibria

Carleton College

University of Central Florida

Brown University

University of Toronto

Lectures

00:41

In chemistry, an ion is an atom or molecule that has a non-zero net electric charge. The name was coined by John Dalton for ions in 1808, and later expanded to include molecules in 1834.

24:14

In chemistry, a buffer is a solution that resists changes in pH. Buffers are used to maintain a stable pH in a solution. Buffers are solutions of a weak acid and its conjugate base or a weak base and its conjugate acid, usually in the form of a salt of the conjugate base or acid. Buffers have the property that a small change in the amount of strong acid or strong base added to them results in a much larger change in pH. The resistance of a buffer solution to pH change is due to the fact that the process of adding acid or base to the solution is slow compared to the rate at which the pH changes. In addition to this buffering action, the inclusion of the conjugate base or acid also slows the process of pH change by the mechanism of the Henderson–Hasselbalch equation. Buffers are most commonly found in aqueous solutions.

01:57

Look up the $K_{\mathrm{…

02:00

Look up the $K_{\mathrm{sp…

02:42

Refer to the $K_{\text {sp…

03:06

Refer to the K_{\text { sp…

03:09

Refer to the $K_{\mathrm{s…

02:17

- The $K_{\text {sp }}$ va…

Hello. So today we're going to be looking at the solution where we've dissolved barium sulphate and strong Tim sulfate. We're going to be looking, but what Concentration of burying two plus strong tea in two plus end sulphate to minus is in the solution. So we have a common eye on here. So first to let's right, the equilibrium that's going on here. So we've got sulfate associating to bury him two plus and self eight and the Kiss P here Barbarian sulphate is one 0.1 times 10 to the negative 10. Now let's take a look at strong teams sulphate, strontium sulphate associates, much like Barry himself. Eight on the case P first drawn to him sulphate is three 0.8 times 10 to the negative seven. So if we look at these chaos p values, you will notice that the cast p for strong team sulfate is a lot larger than the Caspi. For barium sulfate, it's 10 to the third, almost more so almost 1000 times bigger. So so basically, let's assume for a second that most of the sulphate is coming from the strong Tim sulphate. So if we know the Caspi and It's just wrong tm and sulfates. So let's figure out so 3.8 times 10 to the negative seven and the concentration of strong team and sulphate to we're going to assume is around the same. And if we take a square root of both sides, we'll see that acts, which is equal to the concentration of strong team and the concentration of sulphate, is equal to six 0.2 times 10 to the negative four. Similarity. So now that we have the concentration of the strong team two plus in the sulfate, let's take a look at the concentration of varying two plus. So the cast P is 1.1 times 10 to the negative 10 in this well, very M two plus is what we're trying to find out. And the sulfates comes from the more soluble salts strong team, and we know that concentration of that 6.2 times 10 to the negative four. So the concentration of barium two plus is one 0.8 times 10 to the negative seven hilarity. So now we know the concentrations and you'll see. Conversely, you can also use the fact that the concentration of strong team is equal to barium two plus and plus the concentration of strong team two plus and the equations you get from the K S. P. And you cannot solve that that system of equations. But you would get the same answer as we did from assuming that all of so self fate came from the strong team sulfate.

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