Question
Loudspeaker A loudspeaker diaphragm is oscillating in simple harmonic motion described by the equation $d=a \cos (\omega t)$ with a frequency of 520 hertz (cycles per second) and a maximum displacement of 0.80 millimeter. Find $\omega$ and then determine the equation that describes the movement of the diaphragm.
Step 1
We know that the frequency $f$ is related to $\omega$ by the equation $f = \frac{\omega}{2\pi}$. Given that the frequency is 520 hertz, we can substitute this into the equation and solve for $\omega$: $$ 520 = \frac{\omega}{2\pi} $$ Show more…
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