00:01
In this problem, we are given the 3d structure of ephedrine, which is represented by the ball and stick model.
00:14
First, we need to determine out of the ball and stick model the molecular formula.
00:24
So you have to count the number of each type of atoms, the number of carbon, the number of hydrogen, and the number of nitrogen.
00:33
And also the number of oxygen.
00:36
So there are four carbons represented in the structure.
00:40
When you count that, you get that you have 10 carbons, 15 hydrogens, one nitrogen, and one oxygen.
00:54
And this is the molecular formula of effigrine.
01:02
Next, we have to draw the structure of effigris.
01:09
The structure formula of effigrine in other words we have to convert the 3d structure in a 2d or planar structure so the first thing we see is a bengen group or a bengen ring which is drawn like this okay and then we have five hydrogens coming out of the bengen ring in the bengen ring each vertex here is a carbon okay it's an atom of carbon each one of this vertex here is an atom of carbon this carbon and each of this carbon is bound to a hydrogen this carbon however is not bound to a hydrogen but rather to another carbon and this carbon is bound to an oxygen which is further bound to a hydrogen this carbon is also bound to another carbon and another hydrogen here.
02:35
This carbon is bound to another carbon, which is bound to three hydrogens.
02:49
This carbon is bound to another hydrogen here, a nitrogen, and this nitrogen is bound to a hydrogen and another methyl group, which is a carbon, and three, bound to three, and three hydrogens.
03:15
So let's just verify that this drawing coincide with the molecular formula.
03:23
So let's count the number of carbon.
03:25
One, two, three, four, five, six, which makes, which made the benzene green.
03:31
Seven, eight, nine, ten carbon.
03:36
Now hydrogens.
03:38
One, two, three, four, five, six, seven, 8, 9, 10, 11, 12, 13, 14, 15, 15, 15 hydrogen.
03:50
One nitrogen is here, when oxygen is here.
03:55
So we're good.
03:57
Next, we have to calculate the molar mass of this compound.
04:04
The molar mass is the sum of all the atomic masses represented by the atoms here.
04:12
So for carbon, we have 10 carbons and each carbon weighs 12 grams.
04:22
That's the atomic mass of carbon.
04:23
Carbon is weight 12 grams per mole and we have 10 of those, 10 carbons...